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Systems of Linear Equations in Two Variables

Systems of linear equations in two variables

3.5 Explain systems of linear equations in two variables and their solutions in contextual problems.

4.5 Solve problems related to systems of linear equations in two variables.

After studying this material, students are expected to be able to:

  1. explain the meaning of a linear equation in two variables,
  2. explain the general form of a system of linear equations in two variables,
  3. solve SLETV problems using graph, substitution, elimination, and mixed methods,
  4. solve word problems related to systems of linear equations in two variables.

Observe the following equations.

  1. 2x+2y=12x + 2y = 1
  2. mnn2=5\dfrac{m}{n} - \dfrac{n}{2} = 5
  3. 5p+6q=205p + 6q = -20

Each equation has two variables, and each variable has degree one. Therefore, they are examples of linear equations in two variables.

Note

A linear equation in two variables can be written in the general form ax+by=cax + by = c with a,b,cRa,b,c \in \mathbb{R}, a0a \neq 0, and b0b \neq 0.

The solution of a linear equation in two variables can be found by inspection or by algebraic operations.

Determine the non-negative integer solutions (x,y)(x,y) that satisfy:

4x+3y=12 4x + 3y = 12

If x=0x=0, then:

4x+3y=120+3y=123y=12y=4 \begin{aligned} 4x + 3y &= 12 \\ 0 + 3y &= 12 \\ 3y &= 12 \\ y &= 4 \end{aligned}

If x=3x=3, then:

4x+3y=124(3)+3y=1212+3y=123y=0y=0 \begin{aligned} 4x + 3y &= 12 \\ 4(3) + 3y &= 12 \\ 12 + 3y &= 12 \\ 3y &= 0 \\ y &= 0 \end{aligned}

So, the solution set is:

{(0,4),(3,0)} \{(0,4),(3,0)\}

A system of linear equations in two variables is a collection of two or more linear equations that use the same variables.

General form

>{>>a1x+b1y=c1>a2x+b2y=c2>>> > \left\{ > \begin{aligned} > a_1x+b_1y&=c_1 \\ > a_2x+b_2y&=c_2 > \end{aligned} > \right. >

Examples:

  1. {2x+y=53x+5y=4\left\{\begin{aligned}2x+y&=-5\\3x+5y&=-4\end{aligned}\right.
  2. {y=3x22x+y=8\left\{\begin{aligned}y&=3x-2\\2x+y&=8\end{aligned}\right.

Systems of linear equations in two variables can be solved by:

  1. graph method,
  2. substitution method,
  3. elimination method,
  4. mixed method.

In the graph method, the solution is the intersection point of the two lines on the Cartesian plane.

Find the solution set of:

{x+y=5xy=1 \left\{ \begin{aligned} x+y&=5 \\ x-y&=1 \end{aligned} \right.

For the equation x+y=5x+y=5:

x05
y50
(x, y)(0, 5)(5, 0)

For the equation xy=1x-y=1:

x01
y-10
(x, y)(0, -1)(1, 0)

The graph is as follows.

SLETV graph

The two lines intersect at (3,2)(3,2). Therefore, the solution set is:

{(3,2)} \{(3,2)\}

The substitution method is done by expressing one variable in terms of the other, then substituting it into the second equation.

Solve:

{5x+5y=25(1)3x+6y=24(2) \left\{ \begin{aligned} 5x+5y&=25 \qquad (1)\\ 3x+6y&=24 \qquad (2) \end{aligned} \right.

From equation (1)(1):

5x+5y=255y=255xy=5x \begin{aligned} 5x+5y &= 25 \\ 5y &= 25-5x \\ y &= 5-x \end{aligned}

Substitute y=5xy=5-x into equation (2)(2):

3x+6y=243x+6(5x)=243x+306x=243x=6x=2 \begin{aligned} 3x+6y &= 24 \\ 3x+6(5-x) &= 24 \\ 3x+30-6x &= 24 \\ -3x &= -6 \\ x &= 2 \end{aligned}

Substitute x=2x=2 into equation (1)(1):

5(2)+5y=2510+5y=255y=15y=3 \begin{aligned} 5(2)+5y &= 25 \\ 10+5y &= 25 \\ 5y &= 15 \\ y &= 3 \end{aligned}

So, the solution set is:

{(2,3)} \{(2,3)\}

The elimination method removes one variable by making its coefficients equal first if necessary.

Solve:

{2x+y=8xy=10 \left\{ \begin{aligned} 2x+y&=8 \\ x-y&=10 \end{aligned} \right.

Add the equations to eliminate yy:

2x+y=8xy=103x=18 \begin{aligned} 2x+y &= 8 \\ x-y &= 10 \\ \hline 3x &= 18 \end{aligned}

Hence:

x=6 x=6

Now eliminate xx by multiplying the second equation by 2:

2x+y=82x2y=203y=12 \begin{aligned} 2x+y &= 8 \\ 2x-2y &= 20 \\ \hline 3y &= -12 \end{aligned}

So:

y=4 y=-4

Therefore, the solution set is:

{(6,4)} \{(6,-4)\}

The mixed method combines elimination and substitution.

Solve:

{2x+y=5(1)3x2y=11(2) \left\{ \begin{aligned} 2x+y&=5 \qquad (1)\\ 3x-2y&=11 \qquad (2) \end{aligned} \right.

Make the coefficients of xx equal:

6x+3y=156x4y=22 \begin{aligned} 6x+3y &= 15 \\ 6x-4y &= 22 \end{aligned}

Subtract the equations:

6x+3y=156x4y=227y=7 \begin{aligned} 6x+3y &= 15 \\ 6x-4y &= 22 \\ \hline 7y &= -7 \end{aligned}

Thus:

y=1 y=-1

Substitute into equation (1)(1):

2x+y=52x1=52x=6x=3 \begin{aligned} 2x+y &= 5 \\ 2x-1 &= 5 \\ 2x &= 6 \\ x &= 3 \end{aligned}

So, the solution set is:

{(3,1)} \{(3,-1)\}

Word problems involving SLETV are solved by first creating a mathematical model and then solving the resulting system.

The price of five tables and eight chairs is Rp1,150,000.00, while the price of three tables and five chairs is Rp700,000.00. Determine the price of each table and chair.

Let:

  • table price = xx
  • chair price = yy

Then:

{5x+8y=1.150.000(1)3x+5y=700.000(2) \left\{ \begin{aligned} 5x+8y&=1.150.000 \qquad (1)\\ 3x+5y&=700.000 \qquad (2) \end{aligned} \right.

Multiply equation (1)(1) by 3 and equation (2)(2) by 5:

15x+24y=3.450.00015x+25y=3.500.000 \begin{aligned} 15x+24y &= 3.450.000 \\ 15x+25y &= 3.500.000 \end{aligned}

Subtract:

15x+25y=3.500.00015x+24y=3.450.000y=50.000 \begin{aligned} 15x+25y &= 3.500.000 \\ 15x+24y &= 3.450.000 \\ \hline y &= 50.000 \end{aligned}

Substitute y=50,000y=50{,}000 into equation (2)(2):

3x+5y=700.0003x+5(50.000)=700.0003x+250.000=700.0003x=450.000x=150.000 \begin{aligned} 3x+5y &= 700.000 \\ 3x+5(50.000) &= 700.000 \\ 3x+250.000 &= 700.000 \\ 3x &= 450.000 \\ x &= 150.000 \end{aligned}

Therefore:

  • table price = Rp150,000.00
  • chair price = Rp50,000.00
  1. The sum of two numbers is 28 and their difference is 12. The numbers are … A. 8 and 20
    B. 10 and 18
    C. 12 and 16
    D. 14 and 14

  2. Ali is 30 years old now. Six years ago, Ali’s age was three times Budi’s age. Budi’s current age is … A. 8 years
    B. 10 years
    C. 14 years
    D. 24 years

  3. Observe the following graph.

SLETV evaluation graph

The equation that matches the graph is … A. 2x+3y=32x+3y=3
B. 2x+y=92x+y=9
C. 2x+y=32x+y=3
D. 3x+y=23x+y=2

  1. The solution set of 3x2y=73x-2y=7 and 2x+y=142x+y=14 is {(a,b)}\{(a,b)\}. The value of a+ba+b is … A. 9
    B. 7
    C. 5
    D. 4

  2. On a farm there are 13 animals consisting of chickens and goats. The total number of legs is 38. The number of goats is … A. 5
    B. 6
    C. 7
    D. 8

That concludes this material on systems of linear equations in two variables.

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