Contents

Prism

This lesson covers the definition of a prism, its parts, diagonals, nets, surface area, volume, and volume changes.

3.9 Distinguish and determine the surface area and volume of polyhedra such as cubes, cuboids, prisms, and pyramids.

4.9 Solve problems related to the surface area and volume of those solids and their combinations.

After studying this material, students are expected to be able to:

  1. Identify faces, edges, plane diagonals, space diagonals, diagonal planes, and prism height.
  2. Draw prism nets.
  3. Determine the surface area of a prism.
  4. Derive and use the formula for the volume of a prism.
  5. Determine how prism volume changes when the base or height changes.

Right prism

A prism is a polyhedron with two congruent and parallel faces, and lateral edges that are parallel to one another.

Based on the direction of the lateral edges, prisms are divided into:

  1. Right prisms, whose lateral edges are perpendicular to the base and top faces.
  2. Oblique prisms, whose lateral edges are not perpendicular to the base and top faces.

Oblique prism

Prisms are named after the shape of their base, such as triangular prisms, rectangular prisms, pentagonal prisms, and so on.

Parts of a prism

For the rectangular prism ABCD.EFGHABCD.EFGH:

  1. Points A,B,C,D,E,F,G,A, B, C, D, E, F, G, and HH are the vertices.
  2. ABCDABCD is the base face.
  3. EFGHEFGH is the top face.
  4. ABFEABFE, BCGFBCGF, CDHGCDHG, and ADHEADHE are the lateral faces.
  5. AB\overline{AB}, BC\overline{BC}, CD\overline{CD}, and AD\overline{AD} are the base edges.
  6. EF\overline{EF}, FG\overline{FG}, GH\overline{GH}, and EH\overline{EH} are the top edges.
  7. AE\overline{AE}, BF\overline{BF}, CG\overline{CG}, and DH\overline{DH} are the lateral edges.
  8. The prism height (t)(t) is the distance between the base and top faces. In a right prism, it equals the length of a lateral edge.

Prism diagonals

In prism KLMNO.PQRSTKLMNO.PQRST:

  • KM,LN,MO,LO,\overline{KM}, \overline{LN}, \overline{MO}, \overline{LO}, and KN\overline{KN} are diagonals of the base face.
  • Plane KMRPKMRP is a diagonal plane, a plane containing a diagonal of the base and a corresponding diagonal of the top face.
  • Segments LTLT, LSLS, and KRKR are space diagonals.

Important definitions:

  1. A plane diagonal joins two non-adjacent vertices on the same face.
  2. A space diagonal joins two vertices that do not lie on the same lateral face.
  3. A diagonal plane contains diagonals of the base and top faces.

Prism net

To make a prism net:

  1. Build a prism model from cardboard.
  2. Cut along selected edges.
  3. Unfold the model until all faces lie flat.

For the triangular prism PQR.STUPQR.STU, the surface area is the sum of two bases and all lateral faces:

L=2×base area+base perimeter×prism height \begin{aligned} L &= 2 \times \text{base area} + \text{base perimeter} \times \text{prism height} \end{aligned}

So the formula is:

L=2×base area+base perimeter×height L = 2 \times \text{base area} + \text{base perimeter} \times \text{height}
  1. A triangular prism has a right-triangle base with side lengths 99 cm, 1212 cm, and 1515 cm. Its height is 66 cm. Find the surface area.
  2. Find the surface area of the following prisms.

Trapezoidal prism

Triangular prism

L=(2×base area)+(base perimeter×height)=2×(12×12×9)+(12+9+15)×6=108+216=324 \begin{aligned} L &= (2 \times \text{base area}) + (\text{base perimeter} \times \text{height}) \\ &= 2 \times \left(\frac{1}{2} \times 12 \times 9\right) + (12 + 9 + 15) \times 6 \\ &= 108 + 216 \\ &= 324 \end{aligned}

So the surface area is 324 cm2324\text{ cm}^2.

  1. Trapezoidal prism:
Base area=12×(4+9)×12=78 \text{Base area} = \frac{1}{2} \times (4 + 9) \times 12 = 78 L=(2×78)+(4+13+9+12)×10=156+380=536 \begin{aligned} L &= (2 \times 78) + (4 + 13 + 9 + 12) \times 10 \\ &= 156 + 380 \\ &= 536 \end{aligned}

So the surface area is 536 cm2536\text{ cm}^2.

Triangular prism:

L=2×(12×3×4)+(3+4+5)×6=12+72=84 \begin{aligned} L &= 2 \times \left(\frac{1}{2} \times 3 \times 4\right) + (3 + 4 + 5) \times 6 \\ &= 12 + 72 \\ &= 84 \end{aligned}

So the surface area is 84 cm284\text{ cm}^2.

Prism volume

The volume formula is:

V=base area×height V = \text{base area} \times \text{height}
  1. Find the volume of a prism with height 66 cm and a right-triangle base whose perpendicular sides are 44 cm and 33 cm.
  2. Find the volume of a prism with base area 30 cm230\text{ cm}^2 and height 22 cm.
  3. Find the volume of the prism shown below.

Pentagonal prism

  1. Base area:
12×4×3=6 \frac{1}{2} \times 4 \times 3 = 6

Volume:

V=6×6=36 V = 6 \times 6 = 36

So the volume is 36 cm336\text{ cm}^3.

V=30×2=60 V = 30 \times 2 = 60

So the volume is 60 cm360\text{ cm}^3.

  1. Consider ABL\triangle ABL. Since it is isosceles:
LM2=10262=10036=64LM=8 \begin{aligned} LM^2 &= 10^2 - 6^2 \\ &= 100 - 36 \\ &= 64 \\ LM &= 8 \end{aligned}

Area of ABL\triangle ABL:

12×12×8=48 \frac{1}{2} \times 12 \times 8 = 48

Since the base consists of 5 congruent triangles:

V=5×48×20=4,800 \begin{aligned} V &= 5 \times 48 \times 20 \\ &= 4{,}800 \end{aligned}

So the volume is 4,800 cm34{,}800\text{ cm}^3.

The volume of a prism depends on the area of its base and its height. If either changes, the volume changes as well.

Example:

A triangular prism has a right-triangle base with side lengths 33 cm, 44 cm, and 55 cm, and prism height 1010 cm. The base is enlarged so the corresponding sides become 66 cm, 88 cm, and 1010 cm, while the height stays the same. Determine:

  1. the ratio of the new volume to the original volume,
  2. the amount of volume change.

Volume ratio:

V2V1=L2×tL1×t=L2L1=12×6×812×3×4=4 \begin{aligned} \frac{V_2}{V_1} &= \frac{L_2 \times t}{L_1 \times t} \\ &= \frac{L_2}{L_1} \\ &= \frac{\frac{1}{2} \times 6 \times 8}{\frac{1}{2} \times 3 \times 4} \\ &= 4 \end{aligned}

Therefore:

V2:V1=4:1 V_2 : V_1 = 4 : 1

Change in volume:

V2V1=4V1V1=3V1=3×12×3×4×10=180 \begin{aligned} V_2 - V_1 &= 4V_1 - V_1 \\ &= 3V_1 \\ &= 3 \times \frac{1}{2} \times 3 \times 4 \times 10 \\ &= 180 \end{aligned}

So the change in volume is 180 cm3180\text{ cm}^3.

Use the following simulation to explore prism surface area and volume. Move the sliders for the triangle base, triangle height, and prism height.

  1. A triangular prism has a right-triangle base with perpendicular sides 77 cm and 2424 cm. If the prism height is 2424 cm, find the surface area.
  2. Find the volume of each prism in the following figures.

Prism evaluation 1

Prism evaluation 2

Prism evaluation 3

That completes this prism lesson. Corrections and suggestions can be shared through the available feedback channel.

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